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5 + (- sqrt(1- x^2- (y- abs(x))^2))cos(30((1-x^2-(y-abs(x))^2))), x is from -1 to 1, y is from -1 to 1.5, z is from 1 to 5
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Google this. (Original Post)
rug
Dec 2014
OP
PoliticAverse
(26,366 posts)1. Should save that for February 14th... n/t
NYC_SKP
(68,644 posts)2. I'll see your equation and raise you THIS!
4 + (- sqrt(1- x^2- (y- abs(x))^2))cos(30((1-x^2-(y-abs(x))^2))), x is from -1 to 1, y is from -1 to 1.5, z is from 1 to 5
rug
(82,333 posts)3. I give. I've exhausted my trigonometry.
pinboy3niner
(53,339 posts)6. Rut-roh, that's a bad sine
You may have to put it in a sling or wear an algebra to avoid an emergency trigeostomy. At least, that's what I figure.
rug
(82,333 posts)8. It is probable that the degree to which you formulated this is exponential.
Scuba
(53,475 posts)9. You're in excellent form tonight.
rug
(82,333 posts)4. On second thought, . . . .
you're on!
exp(-((x-4)^2+(y-4)^2)^2/1000) + exp(-((x+4)^2+(y+4)^2)^2/1000) + 0.1exp(-((x+4)^2+(y+4)^2)^2)+0.1exp(-((x -4)^2+(y- 4)^2)^2)
Now I'm craving something, can quite put my finger on it!
The symmetry, impressive!