Thorium is (since being eliminated from gas mantles) simply thrown away after the Lanthanides from Monzanite is removed.
Basically, on the basis of cost of fuel per watt - the same calculation that people use when they claim that "solar energy is free," Uranium is too cheap to meter.
In fact, Uranium and Thorium are so plentiful that many generations will pass before it can be depleted.
All of this is excellent news of course.
By the way, the US nuclear industry does not "use" 50 million tons of Uranium per year. First off, looking at your links, you really need to make a distinction between pounds and tons. A pound is 1/2000 of a British ton. In any case the energy contained in 50 million tons of Uranium (which would represent about can easily be calculated as follows. A typical fission releases roughly 200 MeV. 1 MeV = 1.602E-13 Joules. There fore the fission of one mole (6.02E23 atoms) of Uranium releases 200 X 1.602E-13 X 6.02E23 = 1.93E13 Joules. One mole of Uranium weighs roughly 238 grams, meaning that the fission yield of totally fissioned Uranium is 1.93E13/238 = 80 billion joules per gram. One pound is roughly equal to 454 grams meaning that one pound of Uranium contains 80 billion X 454 = 3.68E13 Joules. This means that one ton of Uranium completely fissioned is 3.68E13 Joules X 2000 = 7.36X16 Joules.
On the entire planet right now, the energy demand per annum is generally thought to be around 400 exajoules.
http://www.pnl.gov/energy/climate/climate_change-technology_scenarios.pdfSince an exajoule is 1E18 joules, we see that the entire energy demand of the planet would be met, if all of coal mines, oil fields, wind fields, hydroelectric plants were replaced by nuclear plants, by 400E18/7.36E16 = 5440 British tons of Uranium, completely fissioned (some as intermediate Plutonium). This differs from 50 million tons by a factor of 10000. Maybe the nuclear industry is boiling off the atmosphere in the night when no one is looking, say when they're playing pirates in the high seas off Greenland.
Oh well LOL, maybe LMFAO even.
Actually, the nuclear industry only burns about 3 to 5% of the Uranium it puts in the fuel in a given reactor. Thus we see that the industry actually would, if called upon to produce all of earth's energy now, would have in reactors at a given time 5000/0.04 = 125000 british tons. 95% of what came out of the reactor would of course be recyclable, and 5% would be fission products.
Oh, and when you announce that U238 is not fissionable with a knowing snicker, you really ought to specify the speed of the neutrons doing the fissioning. It is true the capture to fission ratio of Uranium-238 is quite low in thermal reactors such as the CANDU, roughly around 1%. However in fast reactors, this ratio approaches 30%, and a considerable number of fissions (and thus a high proportion of the energy) comes from fission of U-238. This behavior is pretty typical of the actinides in general. Np-237, as I'm sure you know, has a thermal neutron capture to fission ratio even smaller than U-238, but has a 40% capture ratio with 1-2 MeV fast fission neutrons. Therefore one can almost obtain criticality with Neptunium, depending on the value of eta, so long as one chooses a point in the spectrum where the capture ration is high and eta is high.
This property of variable cross sections over a range of fission speeds represents the reason why the transuranic distribution of elements in a continuously recycled fast neutron spectrum would have less than 2% Curium and less than 2% Americium, whereas using a thermal spectrum, we would be able to obtain an equilibrium concentration of almost 8% Americium, 30% Curium, with a little Californium thrown in on the side. (Please see Prog. Nucl. Energy, 31, 13, (1997))
But thanks anyway for pointing out that nuclear fuel is really, really, really cheap.