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Was that county's voter turnout 33% before the 7000 or after?

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travelingtypist Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:36 PM
Original message
Was that county's voter turnout 33% before the 7000 or after?
That's the statewide number, 33% voter turnout.

If after these votes are added, the voter turnout percentage is a huge outlier, like up to 45% or something, there's your answer.

They can't fight math.

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PeaceNikki Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:37 PM
Response to Original message
1. Read this sub-thread
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travelingtypist Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:41 PM
Response to Reply #1
6. Thanks. That was very helpful.
It sort of answers my question and yet doesn't. It compares past elections, not the direct voter turnout percentage comparison for this election.

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RagAss Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:37 PM
Response to Original message
2. This is a question for Wisconsin history buffs.
Another one stolen...we lost.
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PeaceNikki Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:39 PM
Response to Reply #2
4. .
Edited on Thu Apr-07-11 08:40 PM by PeaceNikki
do'h misfire.
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rzemanfl Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:38 PM
Response to Original message
3. An innocent woman got prison time in Wisconsin because of
Republican math. Lost her job and her house before she was freed.
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KeepItReal Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:40 PM
Response to Original message
5. Town's pop. 39k .... 14315 total votes... 10859 to R.... 3456 to D candidate
Per Maddow 's show on Brookfield, WI
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bluestate10 Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:45 PM
Response to Original message
7. Even more.
The population of the city that the 10000 republican votes came from is 30,000. If 14,000 votes were cast, nearly half of the population of the city would have voted. Wisconsin democrats better jump on this one, some astounding claims are being made by the republican official.
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subterranean Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:52 PM
Response to Reply #7
8. You mean the population of registered voters, don't you?
Brookfield's population is about 39,000, so 30,000 would be a reasonable estimate for the number of registered voters. 14,000 votes would mean a 47% turnout. That's not out of the realm of possibility, but it's exceptionally high for an election like this, and considerably higher than the statewide turnout of 33%.
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KeepItReal Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 08:54 PM
Response to Reply #8
9. They have reported a 51% turnout for this one town
Eom
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The Magistrate Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 09:07 PM
Response to Reply #8
10. It Seems Unlikely Every Adult Was Registered, Sir
As of June, 2009, there were fewer than seven thousand registered voters in Brookfield. It hard to believe this figure quadrupled and more in the last two years.
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JDPriestly Donating Member (1000+ posts) Send PM | Profile | Ignore Thu Apr-07-11 09:38 PM
Response to Original message
11. As I recall, late, late, late on election night if not early on the day after
the election, all precincts were shown to have reported.

What was the total for Waukesha County at that time? Was the percentage of reported voters 33% of considerably less at that time?

Kloppenburg needs to hire lawyers (if she has not already), get the evidence put under seal and depose the County officer in charge of counting the votes as soon as possible.

This looks very fishy.
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